1+6z^2=3z

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Solution for 1+6z^2=3z equation: 



1+6z^2=3z

We move all terms to the left:

1+6z^2-(3z)=0

a = 6; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·6·1
Δ = -15
Delta is less than zero, so there is no solution for the equation

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